Question

Help?
Determine the zeros of f(x) = x3 - 3x2 - 16x + 48.

Answer 1

take x^2 common from 1st 2 terms
take -16 common from last 2 terms

Answer 2

so, then it's (x - 3 - x + (-3))?

Answer 3

eh ?
it will be
x^2 (x-3) -16(x-3)

Following ?

Answer 4

oh, I get it. But what do I do next?

Answer 5

take (x-3) common out I'd say ?

Answer 6

so then, it'll be (x^2 - 16) ?

Answer 7

actually it'll be

(x^2-16)(x-3)

Answer 8

Hope you can find the zeroes now.

Answer 9

ok, thanks!