What is the solution of the equation? (x-2)^3/4 = 8
is that \[\frac{ (x - 2)^{3} }{ 4 } = 8\] or \[(x - 2)^{3/4} = 8\]
the second one
all right so the left hand side is raised to the 3/4 power. is there a way to invert that? here is an example: \[y^{5/7} = 10 \rightarrow (y^{5/7})^{7/5} = 10^{7/5} \rightarrow y = 10^{7/5}\]
i honestly have no clue what to do..
raise both sides to the 4/3 power. that will cancel the exponents on the left side
so it would look like this: \[(x-2) = 8_{4}^{3}\]
we are raising both sides to the 4/3 power so . . .
\[(x - 2) = 8^{4/3}\]
sorry i got the exponent flipped around... So now what would be the next step?
We can focus on analyzing 8^(4/3). another way of writing 8 to the 4/3 is saying the 3rd root of 8^4 \[8^{4/3} = \sqrt[3]{8^{4}}\]
and without using a calculator .. we could also take note that 8 = 2^3 and rewrite the expression as: \[\sqrt[3]{8^{4}} = \sqrt[3]{(2^{3})^{4}} = \sqrt[3]{2^{3} * 2^{3} * 2^{3} * 2^{3} }\]
taking the cubed root of each factor here: \[\sqrt[3]{2^{3} * 2^{3} * 2^{3} * 2^{3}} = 2 * 2 * 2 * 2 = 16\]
so, when it is all said and done \[8^{4/3} = 16\] and our equation that was (x - 2) = 8^(4/3) is now simplified to (x - 2) = 16
and then you just add 2 to both sides for the final answer?
yep
thank you i appreciate it. i'm gonna write this in my notes so i can remember all that lol
i mean if you could use a calculator it would be a lot easier, but i wasnt sure so i took the long route
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