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OpenStudy (kuoministers):
there is few ways of working this out. Elimination, Substitution and maybe multiplication
OpenStudy (kuoministers):
which way do you prefer?
OpenStudy (anonymous):
i need my mind refreshed. whichever method works best is the method i choose.
OpenStudy (kuoministers):
ill use substitution then :P
x = \[x = y - \frac{ 1 }{ 5 }\]
25x + ky = 4
OpenStudy (kuoministers):
25(y - \[25(y - \frac{ 1 }{ 5 }) + ky = 4\]
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OpenStudy (kuoministers):
\[25y - 5 + ky = 4\]
OpenStudy (kuoministers):
do you get it now?
OpenStudy (anonymous):
howd u get y-(1/5)?
OpenStudy (kuoministers):
divide everything in the first equation by 5
OpenStudy (kuoministers):
there is no solution :)
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OpenStudy (kuoministers):
ill use elimination now
OpenStudy (kuoministers):
times the first equation by -5
-25x - 25y = -5
25x + ky = 4
OpenStudy (kuoministers):
now add this equation vertically together.
it would give you k=25
OpenStudy (anonymous):
i probably shoulda phrased the question the way they have it on my hw.
it says:
Determine the value of k for which the system of linear equations has no solutions.
OpenStudy (kuoministers):
haha great :/
u say that now
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OpenStudy (kuoministers):
you know why there is no solution?
if you sub K = 25 it wont work