Question

Solve and show and explain work

x^2 + bx + c = 0

Answer 1

Try applying the quadratic equation to this one.

Answer 2

@LogicalApple

Answer 3

\[x = \frac{ -b \pm \sqrt{b^{2} - 4ac} }{ 2a }\]

Answer 4

@BubbaMurphy Do you have a different way to do this problem???

Answer 5

LogicApple's way is definitely the way to do it.

Answer 6

in this case, a=1

Answer 7

Is that really how yo would solve it

Answer 8

would A, B, and C = 1

Answer 9

Based on the equation you supplied, a = 1, b = b, and c = c.

Answer 10

They are coefficients of whatever quadratic you are talking about. Did you have a quadratic in mind?

Answer 11

what you mean

Answer 12

\[6x^{2} - 9x + 12 = 0\]
\[-5x^{2} + x - 10 = 0\]
\[x^2 + x - 1 = 0\]

These are some examples of quadratics, all set equal to 0.

Answer 13

Yea I know that

Answer 14

Oh, ok... so what is your question?

Answer 15

We have to solve x^2 + bx + c = 0 for bonus and I have no idea what to do

Answer 16

I suggested using the quadratic equation. The only difference between x^2 + bx + c = 0 and the quadratics that I mentioned is that the coefficients in your equation are only known by their variable letter.

But that is ok, you can still apply the quadratic formula to them.

The solutions to x^2 + bx + c = 0 is:

\[\frac{ -b \pm \sqrt{b^{2} - 4c} }{ 2 }\]

This is the same thing I wrote before, except I let a = 1 because the coefficient of x^2 in your equation is 1.

Answer 17

We didn't learn that equation you gave me

Answer 18

What about completing the square ?

Answer 19

so is that the answer

Answer 20

Yes, but you would arrive at the same answer if you complete the square. Both techniques are valid for solving quadratic equations.

Answer 21

I have to show my work, so how would I show it

Answer 22

Well if you're using the quadratic equation you could say "applying the quadratic equation".

But if you wanted to complete the square then: