Question

sinxcos^2 x = sinx

Answer 1

move the sinx to the LHS(Left Hand Side).

Answer 2

ok, then it becomes a -sinx

Answer 3

Then factorise.

Answer 4

is there an eqiuation?

Answer 5

You have it right in front of you.

Answer 6

\[\sin(x)\cos^{2}(x)-\sin(x)=0\]
Bro I told you to move sinx to the LHS.

Answer 7

How easy is that?

Answer 8

oh

Answer 9

What makes that so hard to do, wehn i told you to move it to the RHS.

Answer 10

when*

Answer 11

Now factorise.

Answer 12

Factorise the sin(x).

Answer 13

@randa.mughrabi

Answer 14

ok, then it becomes sinX(cos^2 x-1) = 1

Answer 15

but then it says find it in the interval (0,2pi)

Answer 16

Yeah worry about that later.

Answer 17

Get to the main course first before doing that delicate stuff later.

Answer 18

and why is it =1

Answer 19

Where'd you get the one from on the other side of the equal sign?

Answer 20

Did you do some magic trick on the equation?

Answer 21

I mean 0

Answer 22

So Sinx=0 right?
And cos^2(x)=1 right?

Answer 23

yes, I see that

Answer 24

And then when you square root both sides in cos^2(x)=1, you get this:
\[\cos(x)=\pm1\]
Right?

Answer 25

yes

Answer 26

yes, and cos is +1 at 0 or 2pi and -1 at pi

Answer 27

\[x=0, \pi, 2\pi\]

Answer 28

Now for sin(x)=0

Answer 29

and sin is 0 at the same 3 points

Answer 30

x=0, pi, 2pi
It will have the same values.
Yeah exactly. Well done mate. Good job.

Answer 31

thanks, i really appreciate it