if h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=-16t^2+14t+1 find the height of the object at the time when the speed is zero.

Question

anonymous · Answer

Hint: speed is zero=means when it is not moving.

whpalmer4 · Answer

One trivial solution is h = 0 :-)

anonymous · Answer

Differentiating with respect to,we will get speed.
Given that speed is zero.
Then we can find time when speed.Equating the gotteb in the equation we will get height.

anonymous · Answer

$$h(t)=-16t ^{2}+14t+1$$

anonymous · Answer

$$d[h(t)] \div dt=-(16*2)t+14$$

anonymous · Answer

Here
d[h(t)]÷dt=0

anonymous · Answer

Therefore,
0=-32t+14
t=14/32
Equating t=14/32 in given equation
h(t)=−16t^2+14t+1
h(t)=$$16*(14/32)^{2}+14(14/32)+1$$
=10.1875