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I feel like this doesnt need to be proved since you can just count them, but how do I show that x+x= 2x and in general
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in general, \[\sum_{i-1}^{n} x = nx\]
Using the distributive property.
Or factoring.\[x +x = 1x + 1x = (1 + 1)x = 2x\]
ah I like that, thanks. Very simple.
\[\underbrace{x + x + x + \cdots +x}_{n ~\rm times} = (\underbrace{1 + 1 +1\cdots 1}_{n~\rm times})x = nx\]
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No problem :-)
What you want to prove is an axiom, and you might wanna use other axioms to prove an axiom (that might be harder).
Thats what I am doing I think, using properties of real vector space to show others hold. And it is quite tricky. But thank you for you help!
Heh :-P
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