Suppose a and b vary inversely, and b = 8 when a = 6. Write a function that models the variation and find b when a = 30.
for inverse variation , the product of variables = constant. so here ab = k (a constant) so, can you find 'k' given that b=8,a=6 from ab=k ?
Alright How would i start my problem ?
i gave you start only. For, inverse variation. ab = k put a=6,b=8, then k=.... ?
Oh okay. Hold on let me work it out
do i do it like this (6)(8)=k ?
yes, correct! so, k=... ?
48
correct :) so, your function is ab =48 . for 2nd part , just put a=30 in that function and find b.....
when you mean put a for 30 isnt 6 already a unless i replace it
yes, 8 and 6 are now useless. you have ab = 48 put a= 30 , what you get ?
(30)(8) = 240
8 is useless, keep b as b only so, 30 b=48 got this ? to get b now, divide both sides by 30..
got that. Did what both sides by 30 ?
divide
30/48 ?
30 b/30 = 48/30
48/30 = 1.6
so, b= 8/5 =1.6
how you get b= 8/5 i thought it was 1/6
@hartnn
48 = 6*8 30 =6*5 48/30 = 6*8 /6*5 = 8/5
Oh okay cool. Is this all for part 2 ? And is this all for my answer as well part 1 & 2
yes, thats it... ab = 48 b= 8/5
Thank you so much : )
welcome ^_^
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