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Find the limit as x approaches infinity for (3|x|-2x)/(7x-5). Find the limit now as x approaches negative infinity.
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when x approaches +infinity x > 0 so, |x| = x when x approaches -infinity x < 0 so, |x| = -x
\[\lim_{x \rightarrow \infty} \ \frac{ 3|x|-2 }{ 7x-5 } \] and then the same again for -infinity. I know the answers are -5/7 for negative infinity and 1/7 for positive infinity. I just don't know how to get there. Please don't use l'hopitals or anything. Haven't learned that yet
Oh that makes sense. thanks!
good :) so now can you get those answers ?
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