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Mathematics 18 Online
OpenStudy (anonymous):

Complex number to exponential form: (1+i)^(3/2) Writing this out it becomes sqrt(-2+2i) I need help turning this into an exponential form. I am stuck, please help!

OpenStudy (shubhamsrg):

How does writing that out becomes (-2 + 2i) ?

OpenStudy (shubhamsrg):

oh, didn't see the square root.

OpenStudy (anonymous):

the square root of -2+2i. Because it turns to sqrt[(1+i)^2]

OpenStudy (shubhamsrg):

okay, What you have done is correct, but you could have used euler's formula in the first place only, with (1+i), if you understand what I mean ?

OpenStudy (anonymous):

I am afraid I do not know how to use eulers in this form. All I know is breaking down the exponential of an imaginary

OpenStudy (shubhamsrg):

e^ix = cos(x) + isin(x) right ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so then will it be cos[(-2)^1/2]+isin[sqrt(2)]?

OpenStudy (shubhamsrg):

you have (1+i)^(3/2) can we write it as : |dw:1359133825680:dw| ?

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