Suppose that y varies directly with x and inversely with z, and y = 18 when x = 15 and z = 5. Write the equation that models the relationship. Then find y when x = 21 and z = 7
@Hero
Hint: If y varies directly with x and inversely with z, then: yz = kx Input the given values to find k
18(5) = k(15)?
Yes, now solve for k: (18*5)/15 = k
here are the multiple choice answers. y = 5z/x; 5/32 t = 5x/z;15 t = 6x/z;18 t = 6z/x;2
Solving for k is only part of the problem. Find k, then get back to me.
OK 18 * 5 IS 90/15 = k k = 6 @hero
Okay, good. Now you have to use this formula again: yz = kx except this time use the fact that k = 6, x = 21, and z = 7 to find y
y(7) = 21*6 7y = 126 y = 18
GJ
thanks so the answer t = 6x/z;18
@hero
I don't know where t comes from.
If you have to choose one, then I suppose what you have chosen is correct.
alright is there another way to solve this? that might give a different answer? @Hero
There's only one way to solve it, and I have shown it to you. Your math course is being weird. Trust me. 99% of the world does it the way I've shown you (without the t)
But don't worry. Your answer choice should be correct.
alright thanks hun :P
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