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Physics 19 Online
OpenStudy (anonymous):

6. A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 × 10^3 kg train car moving at 10.0 m/s in the same direction, and the two latch onto each other and continue together. What is their final speed? 16 m/s 6.0 m/s 10 m/s 14 m/s

OpenStudy (anonymous):

using conservation of momentum \[p_1+p_2=p_3\] \[p_3=(m_1+m_2)v_f\]

OpenStudy (anonymous):

\[m_1v_{1i}+m_2v_{2i}=(m_1+m_2)v_f\]

OpenStudy (anonymous):

you have the massed and the velocities , you need final velocity so solving this you for v final is \[v_f=\frac{(m_1v_{1i}+m_2v_{2i})}{(m_1+m_2)}\]

OpenStudy (anonymous):

hope this helps =]

OpenStudy (anonymous):

Thank you so much for your help. That really helped me.

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