Question

Medal will be given!

How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26°C? Show all work used to solve this problem

Answer 1

I'm trying to figure it out.. I just did stuff like this in my Chemistry class

Answer 2

i have no idea O.o i don't have chemistry...

Answer 3

Oakay, well what I know is all temperatures should be in Kelvin not Celsius..

Answer 4

I'm trying to remember if you add 240 or 270

Answer 5

Wow why am I having trouble with this, I'm struggling i'm not sure how to do this, I can't remember

Answer 6

can you tell me what you're trying to find?

Answer 7

n=pV/RT
1 mole of h2O = 18g
18*n= x grams

Answer 8

oh you're doing mole stuff yucky, hold up I'm going thru my notes

Answer 9

I'm sorry I do not know..

Answer 10

To convert C into K, add 273.

Plug into the ideal gas law and solve for moles of water.

convert moles of water into grams of water

Answer 11

Like so?

m = PVM / RT
R = (1atm x 22.4L) / (1mole x 273K) = 0.0821Latm/moleK
T = 26 + 273 = 299K
m = 0.98atm x 10.2L x 18g/mole / (0.0821Latm/molek x 299K) = 7.33gH2O

Answer 12

i get about 7.5g, but that's close enough, given differences in rounding

Answer 13

Ok thanks!

Answer 14

yw