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Physics 13 Online
OpenStudy (anonymous):

In the graph above, how does the acceleration at A compare with the acceleration at B? a. The acceleration at A is positive and less than the acceleration at B. b. The acceleration at B is positive and less than the acceleration at A. c. The accelerations at A and B are each zero. d. The accelerations at A and B cannot be determined.

OpenStudy (anonymous):

OpenStudy (konradzuse):

we just spoke about acceleration. A = Velocity/Time.

OpenStudy (anonymous):

It Doesn't Make Sense To Me In This Way

OpenStudy (konradzuse):

It shows you the velocity on the left, and the time on the bottom... Where the dots are corrispondes to the velocity/time.

OpenStudy (anonymous):

If you look at the graph, you will see that on the x-axis is time, and on the y-axis is the velocity. First, are you familiar with derivatives of functions?

OpenStudy (anonymous):

Well, remember that the acceleration is a measure of how much the velocity changes in time. Looking at point A you see that at that specific point, the velocity does not change in time (the slope of the graph is zero). You can imagine this by taking a point veery close to the left of A, and a point veery close to the right of A. If you look at the change in velocity between those two points close to A, you can see that it is zero. The same applies to point B :)

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