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Algebra 8 Online
OpenStudy (anonymous):

Am I correct??

OpenStudy (phi):

Use FOIL to write the four products (2sqrt(3x)-2) (3 sqrt(3x)+5) First: 2sqrt(3x)* 3 sqrt(3x) Outer: 2sqrt(3x)*5 Inner: -2*3sqrt(3x) Last: -2*5 can you simplify each of these products ?

OpenStudy (anonymous):

what? im confused.. no i cant

OpenStudy (anonymous):

@phi??????

OpenStudy (anonymous):

ANYONE???

OpenStudy (phi):

but right now, try simplifying \[ 2 \cdot \sqrt{3x} \cdot 3 \cdot \sqrt{3x} \]

OpenStudy (phi):

when you multiply, you can change the order, so this is the same as \[ 2 \cdot 3\cdot \sqrt{3x} \cdot \sqrt{3x} \]

OpenStudy (phi):

2 times 3 is easy. It is 6 the square root of something times itself "gets rid of" the square root

OpenStudy (anonymous):

I am only suppose to simplify not solve

OpenStudy (phi):

we are doing your problem step by step. The first step is simplify \[ 2 \cdot 3\cdot \sqrt{3x} \cdot \sqrt{3x} \]

OpenStudy (anonymous):

oh ok

OpenStudy (phi):

yes

OpenStudy (anonymous):

ok so you were saying...

OpenStudy (anonymous):

so is it 6 times 9

OpenStudy (anonymous):

@phi

OpenStudy (phi):

3*3 is 9 sqrt(3) * sqrt(3) is 3 remember: sqrt(this_is_anything) * sqrt(this_is_anything) = this_is_anything try again. and don't forget the x

OpenStudy (phi):

yes, and 6*x*3 is the same as 6*3*x (change the order) and 6*3 is 18, so you get 18x next, simplify this one (we can't do a whole lot with it) 2*sqrt(3x)*5

OpenStudy (anonymous):

(10) (sqrt3x)

OpenStudy (anonymous):

is this right

OpenStudy (phi):

yes. next -2*3sqrt(3x)

OpenStudy (anonymous):

is this (-6x) (3( sqrt3x))

OpenStudy (phi):

you have an extra x. -2*3*sqrt(3x) is just -6 * sqrt(3x) or -6sqrt(3x)

OpenStudy (anonymous):

now what??

OpenStudy (anonymous):

how do i know what the answer is

OpenStudy (phi):

The last one is -2*5, which is -10 let's write down what we got so far, added up 18x + 10sqrt(3x) + -6sqrt(3x) -10 we can simplify this by combining the sqrt(3x)'s we have 10 sqrt(3x) and take away 6 sqrt(3x)'s How many sqrt(3x)'s do we have left ?

OpenStudy (anonymous):

4??

OpenStudy (phi):

yes, but write it 4 sqrt(3x) we simplify 18x + 10sqrt(3x) + -6sqrt(3x) -10 to be 18x +4 sqrt(3x) -10 that is the answer. But watch the video to see how we get the 4 factors that we simplified. See if you can do the steps on your own.

OpenStudy (anonymous):

oh ok i will thanks

OpenStudy (anonymous):

do yuo get this one??

OpenStudy (phi):

use ln(a) + ln(b) = ln(a*b) in other words rewrite the sum of two logs as the log of a times b can you do that?

OpenStudy (anonymous):

no... Im lost

OpenStudy (anonymous):

I have no idea how to do this...

OpenStudy (phi):

OK, here is a lesson on how to interpret a formula if we write ln(a)+ln(b) = ln(a*b) that means look at your problem. If it is ln(some_number) + ln(another_number) you can replace it with ln(some_number times another_number) example: ln(2)+ln(5) can be replace with ln(2*5) or ln(10) now use the rule ln(a)+ln(b) = ln(a*b) on your problem 1n2+1nx=5

OpenStudy (phi):

the rule also works for letters like x

OpenStudy (anonymous):

but what do i do with the =5

OpenStudy (phi):

one step at a time

OpenStudy (anonymous):

@phi??

OpenStudy (phi):

yes, but you replace ln2 + ln x with ln 2x in your equation 1n2+1nx=5

OpenStudy (anonymous):

or what do you mean

OpenStudy (anonymous):

@phi?

OpenStudy (phi):

that is it. you now have ln(2x)= 5 now we want to get rid of the ln (natural log) which is the log base e make each side the exponent of e \[ e^{ln(2x)} = e^5 \] the ugly stuff on the left becomes 2x (e raised to the ln(stuff) is stuff. e undoes the ln) you get 2x = e^5 divide both sides by 2 x= e^5/2

OpenStudy (phi):

you need a calculator and they want the answer round to nearest thousanth if nessasary

OpenStudy (anonymous):

this right

OpenStudy (phi):

\[ x= \frac{e^5}{2} \]

OpenStudy (phi):

e is a number 2.718.... roughly 3 and 3*3*3*3*3 is way bigger than 12

OpenStudy (phi):

remember, you do powers before dividing yes. that is much better.

OpenStudy (anonymous):

oh goood! you had helped me half way on this ... Im confused combine like terms . what is the simpler form of the expression 2(x/2-5)- 3/2(x+7/4)

OpenStudy (phi):

multiply 2 times each thing inside the parens. do the same with the -3/2 can you do that ?

OpenStudy (anonymous):

@phi is it 2 x/2 -10 - 3/2x +21/8

OpenStudy (phi):

yes I would write -3/2 * x as -3x/2 it is clearer that 2 is in the denominator but -3/2 * 7/4 is -21/8 not + but mostly correct. you have so far 2x/2 -10 -3x/2 - 21/8 you can add the x's (they have a common denominator of 2) you can add -10 + -21/8 but first you need to multiply -10 by 8/8

OpenStudy (anonymous):

isnt it -10

OpenStudy (anonymous):

8/8 is 1 times -10

OpenStudy (phi):

yes, but we want -80/8 so you have a common denominator with -21/8

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

what does that mean

OpenStudy (phi):

to add fractions or you could change -21/8 into a decimal number.

OpenStudy (anonymous):

-2.625

OpenStudy (anonymous):

so i would add -2.625 and what??

OpenStudy (phi):

2x/2 -10 -3x/2 - 21/8 numbers to numbers so -10 - 2.625 and x's with x's (2x-3x)/2 or -x/2 -x/2 -12.625 is one way to write it or -x/2 - 101/8 is another way

OpenStudy (anonymous):

is that the answer

OpenStudy (anonymous):

Is this the answer

OpenStudy (anonymous):

@Phi?? I promise this is the last question

OpenStudy (phi):

yes. See my post up above

OpenStudy (anonymous):

oh ok thanks sooooo much!!

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