Use a half–angle identity to find the exact value of sin 105°.
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OpenStudy (anonymous):
105=60+?
OpenStudy (anonymous):
105=60+45
OpenStudy (anonymous):
now we use \[\sin (A+B)=\sin Acos B+\sin Bcos A\]
OpenStudy (anonymous):
wait the question says half angle this is compound angle
OpenStudy (anonymous):
sin(60+45) = sin60cos45 + sin60cos45
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OpenStudy (anonymous):
this way will work but the question is looking for the 1/2 angle identity
OpenStudy (anonymous):
oh my gosh! YES! hahaha tats what i cant figure out the half angle identity to use for this problem.
OpenStudy (anonymous):
*thats
OpenStudy (anonymous):
\[\sin(A)=\sqrt{\frac{ 1-\cos 2A }{ 2 }}\]
OpenStudy (anonymous):
so let A=105 then 2A=210
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OpenStudy (anonymous):
so it would be -1/2 radical 2+radical 3 ?
OpenStudy (anonymous):
2+radical3 being under a radical
OpenStudy (anonymous):
if you have a calculator find cos(210) or you rewrite it as cos(180+30)="-(sqrt(3)/2)".
So plugging this value into jonask's equation will give you the answer
OpenStudy (anonymous):
1/2 2+radical 3 . thats my answer
OpenStudy (anonymous):
this one is right :) \[\sqrt{2+\sqrt{3}}\div2 \]
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