Write the standard equation of the circle graphed below. A. Identify the center of the circle B. Determine the radius of the circle. Use the point marked on the graph (-11, 6) in your work C. Write the equation of the circle Thank you!
What is the center of the circle?
on the diagram (-5,2)
What is the radius of the circle?
@Jonask Why are you answering the question instead of the asker?
sorry
The radius is (-6, 2) but it says to use the point marked on the graph (-11, 6) and I don't know why I need to do that
@Mertsj could you please still help me with this?
The radius is a length not an ordered pair. To find the radius you need to find the distance from the center to a point on the circle?
So find the distance from (-5,2) to (-11,6)
24 square units
didnt @blossombuttercupandbubbles1234 say radius is (-6,2) but the diagram says (-5,2)
sorrry not radius but center
\[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}\]
Use the given ordered pairs in the distance formula I just posted to find the radius.
@Mertsj I'm going to try that right now
ok. good
Distance= 7.21
Well, actually it is sqrt 52 and since we are going to need radius squared in the equation of the circle, we should just leave it in that form.
Now here is the equation of a circle: \[(x-h)^2+(y-k)^2=r^2\]
is the center really (-5,2) or is it (-6.5, 2)?
(h,k) is the center and r is the radius.
From the diagram, I would say it is the labelled point which is (-5,2)
How do I fill in the variables? I know H and K is center so H would be -5 and K would be 2 radius r would be square root of 52 what is x and y in the equation?
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