The product of two consecutive whole numbers is 1.5 times greater than the square of the smaller number. Find the two numbers
When you have a problem that involves "two consecutive whole numbers", a good way to start is to think of them as variables... such as N and N+1. Then you can set up the rest of the problem using those variables.
So, in this case, if N is one number, then N+1 would be the next consecutive whole number. So the product of the two would be N * (N+1) And the square of the smaller would be N * N.
And the problem tells you how to relate these two quantities... the product is 1.5 times larger than the square of the smaller... N * (N + 1) = 1.5 * N * N So then you can simplify and solve for N... then the other number is just one larger... N+1
n = 0 and 2 is that right?
@jakev8
Im sorry @jakev8 for jumping into this. But yeah, 0 and 2 isnt right. Try solving out the equation for N like he said above
@incomplte Thanks for helping... my page froze and I couldn't get it to reload.
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