Question

integral (1/(1+rad(2x))dx
use u-sub
what did they do here?

Answer 1

where did the u-1 come from?

Answer 2

\[\int\limits \frac{ 1 }{ 1+\sqrt{2x} }dx???\]

Answer 3

yeah

Answer 4

I would of used conjugates for this, but if you are using u-sub then
\[u = 1+\sqrt{2x}\]
\[(u-1)=\sqrt{2x}\]
what they did there was just find a substitute. Since you don't have anything you can substitute for sqrt, they just rearranged it. So you would get:\[\int\limits \frac{ 1 }{ 1+(u-1) }du\]

Answer 5

If you said u=sqrt(x), then du cant be = dx,

i feel like the question is somewhat wrong lol

Answer 6

The original problem might be off, but that's the same idea. I would of multiplied by conjugates.

Answer 7

*would have
i would too, but that's what the directions say

if u = 1-rad(2x)
du = [(1/2)(2x)^-1/2(2])dx
du = x^-1/2
rad(2x)du = dx

oh wait. i think i get it now.
-_-