Use the image shown below to answer the question that follows. The two-column proof below proves the following theorem: The three medians of a triangle all intersect in one point. Statements Reasons Point F is a midpoint of Point E is a midpoint of Draw Draw By Construction Point G is the point of intersection between and Intersecting Lines Postulate Draw By Construction Point D is the point of intersection between and Point H lies on such that By Construction and Midsegment Theorem and Substitution BCGH is a para
ignore the weird part im gonna retype it
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so you just want to fill in that empty reason?
yeah heres the options By Construction Properties of a Parallelogram Midsegment Theorem Intersecting Lines Postulate
which one do you think it is
i know it isnt by construction
wait
hold on
ok
how is point D an intersection for segment AG when it doesnt extend to d
good thinking, but AG is NOT a segment when they write |dw:1359168842839:dw| it's actually a line
so they are saying it does expand past the d?
yes it extends infinitely in both directions
well in a sense that was constructed
what you construct is what you draw with a pencil, straightedge and compass
can you just plot D anywhere you like?
if you could, then you'd be creating the point D by construction
ok so i guess that isnt what they are looking for...i guess the intersecting lines postulate would make sense..it's simple but it works
and that's the correct answer, to make sure that point D is on both lines, you would just intersect them
that locks D in so to speak to that one spot only
ok thanks
The answer is (Intersecting Lines Postulate)
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