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Integrals and linear algebra?
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I can't figure out the damn matrix lol.
Please help.
Are we missing part (a)?
Okay, I guess I should include that.
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i think it is just \([\frac{8}{3},2,2]\)
i think so too. It's 5 marks though. Is it really that easy?
because if you multiply that by \([a,b,c]\) written of course as a column, you get just what you want
Here is part a. I don't think it's required though.
Hmm, Feels too easy lol.
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Thanks!
it does seem easy, but i am fairly sure it works right?
Yeah it does.
ok
Can you answer another question similar to that?
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i dunno my linear algebra is sometime weak, but i can try
@tkhunny
So f(0)=c f(1)=a+b+c f(2)=4a+2b+c
so: |dw:1359170790953:dw|
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