Question

is this a true or false statement? "If lim f(x) as x->c exist, then lim sqr[f(x)] exist"

Answer 1

no calculus help here? lol

Answer 2

let f(x) be x-1 and let c =0, can you check that statement now ?

Answer 3

no i am still unsure.

Answer 4

i would say false, since counterexamples exist

example:
\[f(x) = \frac{1}{x^{2}}\]
limit as x->0 exists
\[\sqrt{f(x)} = \frac{1}{x}\]
limit as x->0 does not exist

Answer 5

hmm well your example f(x) doesnt exist, and in the statement f(x) does exist. i cant think of an example where f(x) exist and the srt(f(x)) doesnt.

Answer 6

limit of f(x) Does exist ?

lim (1/x^2) as x->0 is positive infinity

Answer 7

correct, your given limit doesnt exist. but in the true/false statement it is stated that f(x) exists, so i dont think your example can be applied to answer this.

Answer 8

what !?!?