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Find the limit as x approaches zero of (the square root of (x^6+9)-3)/x^6
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\[\lim_{x \rightarrow 0}\frac{ \sqrt{x^6+9}-3 }{ x^6 }\] please no l'hopital's rule. I'm suposed to be able to transform it algebraically. The answer is 1/6, I just don't know how to get there
Try to rationalize the numerator.
what does that mean?
multiply and divide by sqrt(x^6 +9) + 3 See if it helps ?
Ok i get to this point:
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\[\frac{ x^6+9-3 }{ x^6(\sqrt{x^6+9}+3) }\]
Is that right and then how do i get past that?
In the numerator, in place of -3, there should be -9 , check that.
got it! thanks!
Glad you did. ^_^
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