What is the equation of the line that passes through the point (4, 1) and has a slope of 5?
y = 5x - 3
y = 5x - 1
y = 5x + 3
y = 5x - 19
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OpenStudy (anonymous):
well what is it? plug in points ;)
OpenStudy (anonymous):
y = 5x - 3
OpenStudy (aravindg):
try again ??
OpenStudy (anonymous):
clue what is the point (0,c) on this line ?
OpenStudy (aravindg):
just plugin the point as @RONNCC said see which equation gets satisfied
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OpenStudy (anonymous):
y = 5x + 3
OpenStudy (aravindg):
1=5*4+3
1=20+3
1=23
nice :)
OpenStudy (aravindg):
dont tell anyone !! ;)
OpenStudy (anonymous):
was that it ?
OpenStudy (aravindg):
do you think 1=23
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OpenStudy (anonymous):
idk
OpenStudy (anonymous):
geometry
OpenStudy (anonymous):
the only way i know is \[y-(y _{1})=m(x-{x _{1})}\] point slope form
OpenStudy (anonymous):
this is algebra
OpenStudy (anonymous):
not geometry
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OpenStudy (anonymous):
@ivandelgado just plug in the points
OpenStudy (zehanz):
Why not use @jalan's formula? It gives you an equation of a line through a given point (x1, y1) with a given slope (m). Fits your problem perfectly!
So put in 5 for m, and x1=4, y1=1 and see what happens.
Of course, you'll have to shuffle this equation a little to see which of the four options it is...
OpenStudy (anonymous):
\[y-(1)={5(x-(4)}\]
OpenStudy (zehanz):
y - 1 = 5(x - 4), yes.
Now expand the brackets...
OpenStudy (zehanz):
@ivandelgado: we've done all we could to help you out here, I think it's your turn now...
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OpenStudy (anonymous):
y = 5x - 19
OpenStudy (zehanz):
Well done!
OpenStudy (zehanz):
And remember that neat little formula y-y1=m(x-x1)...