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Mathematics 5 Online
OpenStudy (anonymous):

Could you help me solve sin(x)>(2x)/pi

OpenStudy (anonymous):

..... what doesn't make sense... what do you want? right now it's just a graph at best

OpenStudy (anonymous):

do you want all x ranges where that is true?

OpenStudy (anonymous):

x is from the interval (0,pi/2), I need to prove that it holds

OpenStudy (anonymous):

well ... do you want an informal proof or a stronger one... just graph it, that's a proof :P / more algebraically is check the endpoints and pi*sin(x) > 2x for that region.

OpenStudy (anonymous):

there are two sets of solutions 0<x<pi/2 and x<-pi/2 the only integer solution is 1

OpenStudy (anonymous):

as to the proof i would also graph it. but you can do it using the trigonometric formulae

OpenStudy (anonymous):

I can't think of any trigonometric transformation, that's my actual problem, could you help?

OpenStudy (anonymous):

that is any trigonometric transformation which is actually useful

OpenStudy (anonymous):

nope sorry. i don't think there is one.

OpenStudy (anonymous):

ok, thanks anyway

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