Question

y varies jointly as x and z, and y = 32 m, x = 6 m, and z = 8 m.

What is the value of y when x = 5 m and z = 12 m?

Answer 1

Can you write the joint variation equation for x y and z? Use k for the constant.

Answer 2

@jim_thompson5910

Answer 3

y=kxz

Answer 4

Now plug in the given values and find k.

Answer 5

does Mertsj's response make sense?

Answer 6

a little, im still a little confused ..

Answer 7

so it would be 32m= k *5m*12m

Answer 8

y = kxz

we're given y = 32 m, x = 6 m, and z = 8 m

plug all this in to get

32 = k*6*8

now solve for k


Note: I think we can ignore the m's because I think they refer to meters (eg: x = 6 m means x is 6 meters long)

Answer 9

4?

Answer 10

no

Answer 11

32 = k*6*8

32 = k*48

k = ??

Answer 12

its 4?

Answer 13

no it's not 4

divide both sides by 48 to solve for k

Answer 14

0.6?

Answer 15

more like 0.667

but I would keep it as a fraction so k = 2/3

Answer 16

y = kxz

y = (2/3)xz

y = (2/3)*5*12 plug in x = 5 and z = 12

y = ???

Answer 17

my choices are 90m, 4m, 40m, 9m

Answer 18

5*12 is what

Answer 19

60

Answer 20

now multiply that by 2

then divide that result by 3

Answer 21

4

Answer 22

close, but not quite

Answer 23

40*

Answer 24

yep

Answer 25

thank you(:

Answer 26

you're welcome