Ask your own question, for FREE!
Trigonometry 9 Online
OpenStudy (anonymous):

solve the inequality. graph your solution. |x+3| > or equal to 15

jimthompson5910 (jim_thompson5910):

Hint: |x| > k breaks into x < -k or x > k where k is some positive number

OpenStudy (anonymous):

is it still correct if the arrows go in the same direction when I graph it?

jimthompson5910 (jim_thompson5910):

no the arrows should be going in opposite directions

OpenStudy (anonymous):

oh so you flip the sign when you make k a negative?

jimthompson5910 (jim_thompson5910):

exactly

jimthompson5910 (jim_thompson5910):

what did you get

OpenStudy (anonymous):

x> or equal to 12 and x < or equal to -18

jimthompson5910 (jim_thompson5910):

good, you got it

OpenStudy (anonymous):

thanks :D

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

find the slope of the line passing through the given points. then tell whether the line rises, falls, is horizontal, or is vertical. (-7,4) (5,-3)

jimthompson5910 (jim_thompson5910):

use the slope formula m = (y2 - y1)/(x2 - x1)

jimthompson5910 (jim_thompson5910):

in this case (x1,y1) = (-7,4) (x2,y2) = (5,-3)

OpenStudy (anonymous):

how do I find out whether the line rises, falls..etc ?

jimthompson5910 (jim_thompson5910):

what did you get for the slope

OpenStudy (anonymous):

-7/12

OpenStudy (anonymous):

oh so the line decreases bc it has a negative slope?

jimthompson5910 (jim_thompson5910):

you nailed it

OpenStudy (anonymous):

Do you mind if i ask you questions from time to time ? I'm trying to study for a trig final on monday.

jimthompson5910 (jim_thompson5910):

sure I can help

OpenStudy (anonymous):

thanks! alright so this question has the same guidelines as the one we just did but with these coordinates (-5/4, 3); (2/3, 3) my friend had an error in her calculator trying to find the slope , but I got m=0 ...im confused

jimthompson5910 (jim_thompson5910):

you're correct, it's 0 how do I know so quickly? notice that the y coordinates are both equal to 3 since the y coordinates are equal, the slope will always be 0 because you have a horizontal line through y = 3

jimthompson5910 (jim_thompson5910):

all horizontal lines have a slope of 0

jimthompson5910 (jim_thompson5910):

using m = (y2 - y1)/(x2 - x1) we get m = (y2 - y1)/(x2 - x1) m = (3 - 3)/(2/3 - (-5/4)) m = 0/(2/3 - (-5/4)) m = 0

OpenStudy (anonymous):

oh ok i understand

OpenStudy (anonymous):

what if the x coordinates are equal? would that make the line vertical?

jimthompson5910 (jim_thompson5910):

exactly

jimthompson5910 (jim_thompson5910):

and the slope would be undefined

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

how would i graph y=|x-3|?

jimthompson5910 (jim_thompson5910):

do you know how to graph y = | x |

OpenStudy (anonymous):

i think so? would there be 2 lines?

jimthompson5910 (jim_thompson5910):

yes here is your blank xy axis |dw:1359244103163:dw|

jimthompson5910 (jim_thompson5910):

the graph of y = | x | looks like this |dw:1359244135745:dw|

jimthompson5910 (jim_thompson5910):

to graph y=|x-3|, you just shift over y = |x| three units to the right

OpenStudy (anonymous):

im not sure i get you there...

jimthompson5910 (jim_thompson5910):

imagine you can pick up that v shaped graph and move it around well just move it over 3 to the right units like this |dw:1359244315265:dw|

OpenStudy (anonymous):

but how do i know the coordinates to create the v shape

OpenStudy (anonymous):

i understand the moving it to the right part

jimthompson5910 (jim_thompson5910):

the sharp point on the V of y = |x| is at (0,0) move that point over 3 units to the right to get (3,0)

jimthompson5910 (jim_thompson5910):

|dw:1359244469161:dw|

OpenStudy (anonymous):

yes i understand that but what are the other coordinates for that shape?

OpenStudy (anonymous):

for (3,0)..

jimthompson5910 (jim_thompson5910):

(1,1) is on the original graph y = |x| move that 3 units to the right to get (4,1)

jimthompson5910 (jim_thompson5910):

|dw:1359244638800:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!