Question

The center of a circle with the equation
(x-6)^2 + (y + 2)^2 = 49 is (6, -2).
True or False
Could you please show me how you got your answer?

Answer 1

(x-6)^2 + (y + 2)^2 = 49

(x-6)^2 + (y - (-2))^2 = 7^2

notice how it matches the form (x-h)^2+(y-k)^2=r^2

(h,k) is the center

so in this problem, h = ?? and k = ??

Answer 2

@jim_thompson5910 yes, what do H and K come out as?

Answer 3

well can you see that h = 6 ?

if so, then k is what number

Answer 4

@jim_thompson5910 k=2?

Answer 5

close, very close

Answer 6

compare

y-k with y - (-2)

Answer 7

-2?

Answer 8

yep

Answer 9

h = 6
k = -2

Answer 10

THANK YOU! You really helped and I learned a lot!

Answer 11

(h,k) is the center

so the center is (6, -2)