How can you put 2(x+1)+0 into the quadratic equation?

Question

abb0t · Answer

distribute the 2 across the parenthesis would be your first step.

anonymous · Answer

I have that, but it doesn't look right, lol.

abb0t · Answer

$$ax^2 +bx +c$$ where quadratic formulas: $$\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

abb0t · Answer

If you don't have an $$ax^2$$ then that must mean that a = 0, right? Since anything multiplied by zero = zero.

abb0t · Answer

But the problem doesn't look right to me either.

anonymous · Answer

So maybe there is no ax^2?

mertsj · Answer

That is not a quadratic equation.  Why would you use the quadratic formula?

abb0t · Answer

@Mertsj is right. You wouldn't use it, but theoretically, right? wouldn't you assume zero for a?

anonymous · Answer

I'n trying to find the graph with a discriminant of 0 and what i gave is the lines equation.

mertsj · Answer

Yes.  If you wanated to put it into quadratic form, a would have to be 0

anonymous · Answer

Okay, thanks. It really confused me. But thanks to both of you!

mertsj · Answer

0x^2+2x + 2 = 0