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x^8 – x^4 + 1001 ≡ 0 (mod 539)
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\(539\;=\;11\cdot 7^{2}\) \(1001\;=\;11\cdot 7\cdot 13\)
I've got to go soon, but you can simplify to \[x^8-x^4+462\equiv 0\pmod{539}\]Then, you can use the quadratic formula to solve for \(x^4\). We get \[\frac{1\pm\sqrt{-1847}}{2}\]However, we're still working in modulo 539, so \(\sqrt{-1847}\equiv \sqrt{309}\pmod{539}\). So you need to solve the congruence \(y^2=309 \pmod{539}\).
That will get you the square root in the quadratic formula, and you can solve from there.
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