Question

Can I factor this by grouping?

Answer 1

25b^2+10b+1?

Answer 2

Can I factor this by grouping? 25b^2+10b+1?

Answer 3

5b+1

Answer 4

b=-1/5

Answer 5

Prime factors of 25 are 5 and 5 so we'll have (5x + a)(5x+b). Multiply that out and you get \[(5x+a)(5x+b) = 25x^2 + 5ax + 5bx + ab\] To make that look like your equation, a and b have to = 1.

Answer 6

25b^2+10b+1
multiply 25 with 1 you will get 25.
now write 10 as the sum of two numbers such that the addition of those numbers result in 10 and the product of those numbers result in 25

Answer 7

I got b(5b+1) 1(b+1) but that does not look correct?

Answer 8

No, (5b+1)(5b+1) is what you want.

Answer 9

(5b+1) and (5b+1) you correct it once again

Answer 10

5b+1)^2?

Answer 11

yes...

Answer 12

Thanks

Answer 13

t(4t+1)=0?
I got t=0, -1/4

Answer 14

ya

Answer 15

Alright cool! Thanks

Answer 16

welcome......

Answer 17

Well, no one really did it the correct way.

Answer 18

25b^2+10b+1
25b^2 +5b+5b+1
5b(5b+1)+1(5b+1)
(5b+1)(5b+1)
(5b+1)^2

Answer 19

No, some of us did it in a way that shows why grouping works :-)

Answer 20

25b25b+5b+1=0
5(5b+1)+1(5b+1)=0
(5b+1)2=0
5b+1=0
5b=-1
b=-1/5

Answer 21

Yes, but you forgot to show the process, which is also important as well @whpalmer4. The question was "How do you factor by grouping?". Showing why it works is fine. Showing the process is equally important.