What is the average (arithmetic mean) of x, y, and z? If x+y=10; y+z=15; x+z=17.
so we are looking for \[\large \dfrac{x+y+z}{2}\]
Can you try to get to this form ?
just give it a try using the given equations
compute sum of them then you have the answer
@Elak any idea?
x+y+y+z+z+x=10+17+15 so its easy to go on!
@amoodarya you just spoiled the questions catch :(
is it 8?
2x+2y+2z=48 x+y+z=48/6 ???
(x+y+z)/3=(10+15+17)/3=42/3=14
:D shame on me :(
other way to compute is solve the system of equation and then calculate mean value
thank you very much AravindG and amoodarya
x+y=10 y+z=15 z+x=17 sum of three eq. is 2(x+y+z)=10+15+17=42 so x+y+z=21 now compare it with first equation
yes, it so easy )))
yw :) and \[\huge \color{green}{\text{WELCOME TO OPENSTUDY!}}\]
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