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OpenStudy (anonymous):
What is the average (arithmetic mean) of x, y, and z? If x+y=10; y+z=15; x+z=17.
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OpenStudy (aravindg):
so we are looking for
\[\large \dfrac{x+y+z}{2}\]
OpenStudy (aravindg):
Can you try to get to this form ?
OpenStudy (aravindg):
just give it a try using the given equations
OpenStudy (amoodarya):
compute sum of them
then you have the answer
OpenStudy (aravindg):
@Elak any idea?
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OpenStudy (amoodarya):
x+y+y+z+z+x=10+17+15
so its easy to go on!
OpenStudy (aravindg):
@amoodarya you just spoiled the questions catch :(
OpenStudy (anonymous):
is it 8?
OpenStudy (anonymous):
2x+2y+2z=48
x+y+z=48/6 ???
OpenStudy (amoodarya):
(x+y+z)/3=(10+15+17)/3=42/3=14
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OpenStudy (anonymous):
:D shame on me :(
OpenStudy (amoodarya):
other way to compute is
solve the system of equation
and then calculate mean value
OpenStudy (anonymous):
thank you very much AravindG and amoodarya
OpenStudy (amoodarya):
x+y=10
y+z=15
z+x=17
sum of three eq. is
2(x+y+z)=10+15+17=42
so x+y+z=21
now compare it with first equation
OpenStudy (anonymous):
yes, it so easy )))
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OpenStudy (aravindg):
yw :) and
\[\huge \color{green}{\text{WELCOME TO OPENSTUDY!}}\]
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