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Mathematics 7 Online
OpenStudy (anonymous):

Need help on two math problems, finding area of the shaded regions?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm not sure what to do

Parth (parthkohli):

Area of a trapezoid for the first problem.

Parth (parthkohli):

Observe that the height is \(2\times \rm radius.\)

Parth (parthkohli):

Trapezium, I mean**

Parth (parthkohli):

\[\dfrac{h}{2}\left(a_1 + a_2\right) = \dfrac{8}{2}\left(17\right)\]

Parth (parthkohli):

Subtract the area of your circle from that.

Parth (parthkohli):

And to correct the question, it's not in terms of \(p\); it's in terms of \(\pi\).

Parth (parthkohli):

I'm talking to myself... @SFAdrienne

OpenStudy (anonymous):

I'm following, just waiting for you to finish. :)

OpenStudy (unklerhaukus):

haha

Parth (parthkohli):

Ah! For the second, do you know about area of a triangle and the area of a sector?

OpenStudy (anonymous):

I do.

Parth (parthkohli):

Basically, it'd be the \(\mbox{area of the sector }-\mbox{area of the triangle}\)

Parth (parthkohli):

You're, fortunately, given the area of the sector ;-)

OpenStudy (anonymous):

That makes things easier. I'll try it out.

Parth (parthkohli):

Sure, take the time you need!

OpenStudy (anonymous):

I got 16 for the first.

Parth (parthkohli):

Hmm...?

Parth (parthkohli):

\(16\pi\) is the area of your circle, but how about the trapezium?

OpenStudy (anonymous):

It is? I'm confused.

Parth (parthkohli):

Wait, okay. When you don't know how to do the smart stuff, start with the dumb stuff.

Parth (parthkohli):

Here, let's look at this example:|dw:1359291849206:dw|

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