Mathematics
7 Online
OpenStudy (anonymous):
Need help on two math problems, finding area of the shaded regions?
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
I'm not sure what to do
Parth (parthkohli):
Area of a trapezoid for the first problem.
Parth (parthkohli):
Observe that the height is \(2\times \rm radius.\)
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Parth (parthkohli):
Trapezium, I mean**
Parth (parthkohli):
\[\dfrac{h}{2}\left(a_1 + a_2\right) = \dfrac{8}{2}\left(17\right)\]
Parth (parthkohli):
Subtract the area of your circle from that.
Parth (parthkohli):
And to correct the question, it's not in terms of \(p\); it's in terms of \(\pi\).
Parth (parthkohli):
I'm talking to myself... @SFAdrienne
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OpenStudy (anonymous):
I'm following, just waiting for you to finish. :)
OpenStudy (unklerhaukus):
haha
Parth (parthkohli):
Ah!
For the second, do you know about area of a triangle and the area of a sector?
OpenStudy (anonymous):
I do.
Parth (parthkohli):
Basically, it'd be the \(\mbox{area of the sector }-\mbox{area of the triangle}\)
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Parth (parthkohli):
You're, fortunately, given the area of the sector ;-)
OpenStudy (anonymous):
That makes things easier. I'll try it out.
Parth (parthkohli):
Sure, take the time you need!
OpenStudy (anonymous):
I got 16 for the first.
Parth (parthkohli):
Hmm...?
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Parth (parthkohli):
\(16\pi\) is the area of your circle, but how about the trapezium?
OpenStudy (anonymous):
It is? I'm confused.
Parth (parthkohli):
Wait, okay.
When you don't know how to do the smart stuff, start with the dumb stuff.
Parth (parthkohli):
Here, let's look at this example:|dw:1359291849206:dw|