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Differentiate: y= -8tan(cosx)
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use the chain rule : derivative of cos(...) is -sin(...) derivative of tan(..) is sec^2 (..)
but the tan encompasses the entire (cos x)....
Repeated chain rule.
let cosx = u derivative of tan(u) = sec^2 u subtitute back u =cosx
ummm. ok lemme try that out. I'll post the answers iiget when i'm done.
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@ParthKohli so dy/dx= [(-sinx)(-8sec^2(cosx))]
Yes! Now simplify it and you are done.
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