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OpenStudy (anonymous):
isnt this the solution then
OpenStudy (anonymous):
since
\[f(9)-2f(11)=3662\]
\[f(10)=3662+11^3-10^3\]
Parth (parthkohli):
OMG!
Parth (parthkohli):
But it's an integer between 0 and 999.
OpenStudy (anonymous):
okay so we found a relationship between numbers 2 units away from each other x-1 and x+1
\[\color{blue}{f(x-1)+x^3=2f(x).......... f(x)+(1+x)^3=2f(1+x)}\]
\[f(x-1)+x^3=4f(x+1)+2(x+1)^3\]
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OpenStudy (anonymous):
\[f(9)-4f(11)=2(11)^3-10^3\]
OpenStudy (anonymous):
earlier we used 2 not 4
Parth (parthkohli):
Ahhh.
Parth (parthkohli):
@Hero
OpenStudy (anonymous):
Let f(x)=a+bx+cx^2+dx^3
NOTE: f(x) must be a third degree polynomial
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OpenStudy (anonymous):
Now, f(x)+(x+1)^3 =2f(x+1)
OpenStudy (anonymous):
\[\huge f(10)=f(9)-2f(11)+11^3-10^3=???\]
OpenStudy (anonymous):
use it to find a,b,c and d
Parth (parthkohli):
I see, yeah!
OpenStudy (anonymous):
u will get
a=-13
b=9
c=-3
d=1
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Parth (parthkohli):
Equating coefficients
OpenStudy (anonymous):
yep
Parth (parthkohli):
Yay
OpenStudy (anonymous):
now, once u know f(x)
u can find f(10)
OpenStudy (anonymous):
help me i dont get where you get the coeeffients from
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Parth (parthkohli):
@Jonask a technique.\[ax + by = 2x + 3y\]means\[a=2,b=3\]