Question

Vector A is defined as:
(^ as a hat not a power)

A = (x+2y)x^ - (y+3z)y^ + (3x-y)z^

I need a unit vector parallel to A at point P(1,-1,2)

A vector parallel to A would have the same components but magnitude 1 right? So the unit vector would be v^ = A/|A|?

Then how do I account for the point it runs through?

Answer 1

U^ = \[\frac{ A(1,-1,2) }{ \left| A(1,-1,2) \right|}\]

Answer 2

Got it.