Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

Force between 3 point charges:

OpenStudy (anonymous):

|dw:1359306681147:dw|

OpenStudy (anonymous):

Force between charges is given by \[k \left( \frac{ q1q2 }{ d ^{2} } \right)\]

OpenStudy (anonymous):

I need the force on q3 due to the other 2 charges. I apparently suck at vector addition and I cant figure this out.

OpenStudy (anonymous):

q1-q3 = \[\sqrt{41}\]

OpenStudy (anonymous):

q3->q2 =\[\sqrt{34}\]

OpenStudy (anonymous):

pooja help me out here! :)

OpenStudy (anonymous):

are q1 q2 and q3 all positive?

OpenStudy (anonymous):

It shouldn't matter for a general force equation, the signs get added later.

OpenStudy (anonymous):

well did they provide you with that information?

OpenStudy (anonymous):

because it effects the direction of the Force vector

OpenStudy (anonymous):

No, I have no charges. All I have is the distances.

OpenStudy (anonymous):

The force vectors equation would be the same right? Just the sign would determine its direction? So a general solution would have a +- out front?

OpenStudy (anonymous):

I mean you can assume either if you can help me find the vector, I dont know how to split components and add vectors anymore because I suck at math.

OpenStudy (anonymous):

The magnitude of the force between q1 and q3 is \[\sqrt{41}\] correct?

OpenStudy (anonymous):

And the magnitude between q2 and q3 is \[\sqrt{34}\]

OpenStudy (anonymous):

Now I need directions, I can find the angles sure, but then how do I combine the 2 vectors?

OpenStudy (anonymous):

oh ok, I did a problem like that yesterday. I'm taking physics II as well |dw:1359308826265:dw| Here I'm assuming that \[+q_1 \:\textrm{and} +q_2 \; \textrm{and} \; +q_3\]

OpenStudy (anonymous):

I didn't split them up into components yet, but do you see what I did?

OpenStudy (anonymous):

Yup I got you so far.

OpenStudy (anonymous):

|dw:1359309165318:dw| ok good! but I hope that q_1 and q_2 and q_3 are positive, because otherwise they'll point the opposite direction.....anyhow....let's continue

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!