Question

Find a string of 100 consecutive positive integers each divisible by a perfect square. Can you find such a set of smaller integers?

Answer 1

{4, 8, 12, ... }

Answer 2

I think it requires that the integers be consecutive. I know this is solvable with the Chinese Number theorem, but I'm not sure how.

Answer 3

can 1 count as a perfect square?

Answer 4

The solution set has to be greater than 1.

Answer 5

so can it be 2 to 101? dey are all divisible by 1^2=1

Answer 6

if not that^ there will be no solution cos out of 100 consecutive numbers... atleast one must be prime

Answer 7

I think this the set includes very large numbers.