Question

help? Find the polynomial function with roots 11 and 2i.

Answer 1

since complex roots come in conjugate pairs, the polynomial has to also have -2i as one of the roots...
so the polynomial having 11, 2i, -2i as roots has to be at least a third degree polynomial

Answer 2

so, it would be (x - 11) (x - 2i) (x - (-2i)) ?

Answer 3

\[(x^3 -11x^2 -2ix^2 +2ix^2 + 22i -22i -4i^2)\] that's the unsimplified answer, so the simplified one is \[(x^3 - 11x^2 -4i^2)\] right?