Question

integral help

Answer 1

\[\int\limits_{-2}^{2} (x^7 +k) dx = 16, \] then k =. . . .

Answer 2

what did u get for the antiderivative for \(\large x^7+k \) ???

Answer 3

hello?

Answer 4

sorry. hold on.

Answer 5

\[\frac{ x^8 }{ 8 } + \frac{ k^2 }{ 2 }\]

Answer 6

not quite..... you're integrating with restpect to x so the k is just a constant....

Answer 7

that second term should be kx... so the anti-derivative is: \(\large \frac{x^8}{8}+kx \)

Answer 8

now... evaluate \(\large [\frac{x^8}{8}+kx]_{-2}^{2}=16 \)

Answer 9

oh! ok! gotcha. thanks!

Answer 10

yw.... :)
did u wanna finish this to check ur answer?