Question

64s^2+144s=-81 can anyone help on this one. Solving for s

Answer 1

64s^2+144s+81=0
(8s+9)^2=0
8s+9=0
8s=-9
s=-9/8

Answer 2

hmmm?

Answer 3

@marsss Thank you for the setup

Answer 4

I think this problem is quadtradic

Answer 5

i believe it is too

Answer 6

@godorovg you're a genius :)

Answer 7

@treydwg you're too :)

Answer 8

thanks lol

Answer 9

so the solution set would be

Answer 10

I working on it

Answer 11

in this problem the first clue is being = 0 usally says Quad needs to be used.

Answer 12

What is the easier way of working out qUADRATIC without using the quad formula?

Answer 13

64^2 is a peferct square so that always tells that this will invole in a square root to slove

Answer 14

you could use a^2+B^2=c^2 as well

Answer 15

So I got -1.125, -1.125. Can I write -1.125^2. Or is this considered incorrect?

Answer 16

yes you can do that with 1.125^2 if you used the Quad form you would plus ninus which is what the problem is asking for..

Answer 17

Ok i just wrote it twice. lets see if it counts it correct?

Answer 18

treydwg first thing to know in this problem 64s^2+144s+81=0 all of the numbers are perfect squares. what that means taking the square root will be a number for example you take square root of 81 which is, we can check this by 9^2 and yes it equals 9.

Answer 19

ok

Answer 20

what about 2v^2+7v+5 and I need tofactor by grouping?

Answer 21

I am at (2v^2+5v)(2v+5) and stuck

Answer 22

@godorovg can you assist?

Answer 23

yes

Answer 24

where do I go from here?

Answer 25

in this problem we need to use F,.O.I .L

Answer 26

ok yes

Answer 27

so now take the 2v^2 and times to 2v what is the answer

Answer 28

4v^2

Answer 29

close try again

Answer 30

4v is right your power is wrong

Answer 31

where are you getting the 2v^2*2v?

Answer 32

because you typed 4v^2 while ago

Answer 33

recall the problem here (2v^2+5v)(2v+5)

Answer 34

yes that what I have

Answer 35

2v(v+5)

Answer 36

the (2v+5) is where im stuck

Answer 37

what can I factor out of that?

Answer 38

now 4v is right because 2v times 2v =4v^2 but that is not what is happening here. You have a power being times by V what is the power of the V? that power of the V is ^1 and when times 2v^2 time 2v = 4v^3

Answer 39

so what happened here is we times the 2's to get 4 and v^2 + v^1 =V^3 see that

Answer 40

let me look at that hold on

Answer 41

ok I see it

Answer 42

now how do I fix the last part?

Answer 43

if you have a question plz ask me..

Answer 44

factoring will not be in use unti we finish F.O.I.L

Answer 45

I have (2v+5) how can I faactor this

Answer 46

no you can not factor that..

Answer 47

ok I see now so this is what I have after foil
4v^3+10v^2+35v

Answer 48

now we can factor

Answer 49

oooooooooh

Answer 50

by grouping?

Answer 51

no grouping there are no a like terms here

Answer 52

I know but i was going to use 35v and try to make another number to group

Answer 53

can not do that srry

Answer 54

ok so wehre from here

Answer 55

no GCF in common

Answer 56

okay let us look at this 4v^3+10v^2+35v what is the same with all the numbers?

Answer 57

v

Answer 58

yes V so how many V's can be factored?

Answer 59

1

Answer 60

v(2v^2+10v+35)

Answer 61

now look at the numbers what can each number be divided by?

Answer 62

v(4v^2+10v+35)

Answer 63

that is the answer it can not be factored any further

Answer 64

ahhhhhhh! Thats my problem i want to always factor further :/

Answer 65

Thank you

Answer 66

treydwg here is a help for you, if you have done all the factoring right than find a number that divides in to the first and see if it works for example 2 will go ino 4 =2 2 will also go into 10 five times but here is a question for you will 2 divide even into 35?

Answer 67

if the answer is no than you are finished..

Answer 68

no it wont and that was my problem

Answer 69

thanks

Answer 70

welcome anytime

Answer 71

before I leave any questions plz ask me

Answer 72

thanks

Answer 73

working on another

Answer 74

If you need help I am here

Answer 75

5x-3=14x+6
I got x=-1

Answer 76

no

Answer 77

5x-3=14x+6 get a like terms together so we x terms let us put the tgether like this 14x-5x=6-3 recall when a + or - crosses the equals sign it changes

Answer 78

x=3/9??

Answer 79

yes that is right

Answer 80

ok i did that one a little wrong thank you

Answer 81

now this one is throwing me off cuz the a^2
I have a^2=10-3a
I got
a^2=5/2

Answer 82

no now think about this one? come you do it!!

Answer 83

ok

Answer 84

first off you can not a^2 = 10 -3a and come out with a^2=5/2 no..

Answer 85

hint what happens to the problem when all nunbers are moved like this a^2+3a-10= what is this problem?

Answer 86

um

Answer 87

what did I say when a problem is set to zero is?

Answer 88

nothing is on one side

Answer 89

or they are all on one side rather

Answer 90

have to factor?

Answer 91

recall the problem a^2 = 10 -3a now look at the problem a^2+3a-10=

Answer 92

0

Answer 93

we have to find something in common

Answer 94

so what type of problem is this? not factoring

Answer 95

quadratic equation

Answer 96

yes

Answer 97

so i need to find out what two numbers product is 10 and sum is 3 right?