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OpenStudy (anonymous):

Express the complex number in trigonometric form. -2

OpenStudy (anonymous):

|dw:1359323411607:dw|

OpenStudy (anonymous):

angle is \(\pi\) and \(|-2|=2\) so \[2\left(\cos(\pi)+i\sin(\pi)\right)\]

OpenStudy (anonymous):

would pi then be 0?

OpenStudy (anonymous):

2(cos 0° + i sin 0°) so that would be the answer

OpenStudy (anonymous):

\(\pi=\pi\) not \(0\) but \(\sin(\pi)=0\)

OpenStudy (anonymous):

?

OpenStudy (anonymous):

if you are working in degrees (which you should not be, but maybe you are) it would be 90 degrees

OpenStudy (anonymous):

zero radians is zero degree \(\pi\) radians is 90 degrees

OpenStudy (anonymous):

oh so it would be 2(cos 90° + i sin 90°) then?

OpenStudy (anonymous):

yes it would

OpenStudy (anonymous):

ok thank you.. could you help me on a few more?

OpenStudy (anonymous):

easy check since \(\cos(90)=-1\) and \(\sin(90)=0\) so you get \(-2=-2\)

OpenStudy (anonymous):

go ahead an post

OpenStudy (anonymous):

Express the complex number in trigonometric form. 3 - 3i

OpenStudy (anonymous):

or Find the cube roots of 27(cos 330° + i sin 330°) show work

OpenStudy (anonymous):

|dw:1359323786322:dw|

OpenStudy (anonymous):

angle for this one is 315 since you seem to be working in degrees

OpenStudy (anonymous):

and \(r=\sqrt{3^2+3^2}=\sqrt{2\times3^2}=3\sqrt{2}\)

OpenStudy (anonymous):

so you get \[3\sqrt{2}\left(\cos(315)+i\sin(315)\right)\]

OpenStudy (anonymous):

so would it be 3sqrt2(cos 7pi/4 +isin7pi/4)?

OpenStudy (anonymous):

for the second one the cubed root of 27 is 3, and \(330\div3=110\) so you get for one cubed root \[3\left(\cos(110)+i\sin(110)\right)\]

OpenStudy (anonymous):

oh now you switch to radians?? yes

OpenStudy (anonymous):

was i right on the other one?

OpenStudy (anonymous):

srry yes

OpenStudy (anonymous):

yes, but it is confusing to use degrees on one question and radians on the next weird

OpenStudy (anonymous):

but if that is how they come, then so be it

OpenStudy (anonymous):

im sorry yeah !

OpenStudy (anonymous):

so for the 2nd question where do i go after that?

OpenStudy (anonymous):

now for the next one, divide the angle by 3 and get 110 that part is easy

OpenStudy (anonymous):

go around the circle again

OpenStudy (anonymous):

330+360 = 690 now divide by 3 and get 230

OpenStudy (anonymous):

so another answer is \[3\left(\cos(230)+i\sin(230)\right)\]

OpenStudy (anonymous):

now one more time

OpenStudy (anonymous):

thatd be the answer for the 2nd one?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

ok thank you!! woulld u no this one Express the complex number in trigonometric form. -6i

OpenStudy (anonymous):

690 + 360 = 1050 divide by 3 and get 350 for the last one

OpenStudy (anonymous):

|dw:1359324405625:dw|

OpenStudy (anonymous):

angle is \(\frac{3\pi}{2}\) or 270 depending on what you are using absolute value is 6

OpenStudy (anonymous):

so you can write \[-6i=6\left(\cos(270)+i\sin(270)\right)\]

OpenStudy (anonymous):

are you doing the same assignment as @lexlover123 ?

OpenStudy (anonymous):

6(cos 270° + i sin 270°) so that would be the answer?

OpenStudy (anonymous):

and whose that? im not sure?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

someone posting almost identical questions here not sure who it is

OpenStudy (anonymous):

gotta run, good luck

OpenStudy (anonymous):

really? thats weird.. but thankyou!! so much!!!

OpenStudy (anonymous):

yw

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