Mathematics
6 Online
OpenStudy (anonymous):
Express the complex number in trigonometric form.
-2
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OpenStudy (anonymous):
|dw:1359323411607:dw|
OpenStudy (anonymous):
angle is \(\pi\) and \(|-2|=2\) so
\[2\left(\cos(\pi)+i\sin(\pi)\right)\]
OpenStudy (anonymous):
would pi then be 0?
OpenStudy (anonymous):
2(cos 0° + i sin 0°) so that would be the answer
OpenStudy (anonymous):
\(\pi=\pi\) not \(0\) but \(\sin(\pi)=0\)
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
if you are working in degrees (which you should not be, but maybe you are) it would be 90 degrees
OpenStudy (anonymous):
zero radians is zero degree
\(\pi\) radians is 90 degrees
OpenStudy (anonymous):
oh so it would be 2(cos 90° + i sin 90°) then?
OpenStudy (anonymous):
yes it would
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OpenStudy (anonymous):
ok thank you.. could you help me on a few more?
OpenStudy (anonymous):
easy check since \(\cos(90)=-1\) and \(\sin(90)=0\) so you get \(-2=-2\)
OpenStudy (anonymous):
go ahead an post
OpenStudy (anonymous):
Express the complex number in trigonometric form.
3 - 3i
OpenStudy (anonymous):
or Find the cube roots of 27(cos 330° + i sin 330°) show work
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OpenStudy (anonymous):
|dw:1359323786322:dw|
OpenStudy (anonymous):
angle for this one is 315 since you seem to be working in degrees
OpenStudy (anonymous):
and \(r=\sqrt{3^2+3^2}=\sqrt{2\times3^2}=3\sqrt{2}\)
OpenStudy (anonymous):
so you get
\[3\sqrt{2}\left(\cos(315)+i\sin(315)\right)\]
OpenStudy (anonymous):
so would it be 3sqrt2(cos 7pi/4 +isin7pi/4)?
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OpenStudy (anonymous):
for the second one
the cubed root of 27 is 3, and \(330\div3=110\) so you get for one cubed root
\[3\left(\cos(110)+i\sin(110)\right)\]
OpenStudy (anonymous):
oh now you switch to radians?? yes
OpenStudy (anonymous):
was i right on the other one?
OpenStudy (anonymous):
srry yes
OpenStudy (anonymous):
yes, but it is confusing to use degrees on one question and radians on the next weird
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OpenStudy (anonymous):
but if that is how they come, then so be it
OpenStudy (anonymous):
im sorry yeah !
OpenStudy (anonymous):
so for the 2nd question where do i go after that?
OpenStudy (anonymous):
now for the next one, divide the angle by 3 and get 110
that part is easy
OpenStudy (anonymous):
go around the circle again
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OpenStudy (anonymous):
330+360 = 690 now divide by 3 and get 230
OpenStudy (anonymous):
so another answer is \[3\left(\cos(230)+i\sin(230)\right)\]
OpenStudy (anonymous):
now one more time
OpenStudy (anonymous):
thatd be the answer for the 2nd one?
OpenStudy (anonymous):
yeah
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OpenStudy (anonymous):
ok thank you!! woulld u no this one
Express the complex number in trigonometric form.
-6i
OpenStudy (anonymous):
690 + 360 = 1050 divide by 3 and get 350 for the last one
OpenStudy (anonymous):
|dw:1359324405625:dw|
OpenStudy (anonymous):
angle is \(\frac{3\pi}{2}\) or 270 depending on what you are using
absolute value is 6
OpenStudy (anonymous):
so you can write
\[-6i=6\left(\cos(270)+i\sin(270)\right)\]
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OpenStudy (anonymous):
are you doing the same assignment as @lexlover123 ?
OpenStudy (anonymous):
6(cos 270° + i sin 270°) so that would be the answer?
OpenStudy (anonymous):
and whose that? im not sure?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
someone posting almost identical questions here
not sure who it is
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OpenStudy (anonymous):
gotta run, good luck
OpenStudy (anonymous):
really? thats weird.. but thankyou!! so much!!!
OpenStudy (anonymous):
yw