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Sketch the graph of f(x) based on f'(x) = 10e^(-2x )- 40
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first i forgot which graph is it that if the line is above x axis, then the slope is increasing, and if the line is below x axis, the slope is decreasing
We know that \(f'(x) = 10e^{-2x} - 40\) and \(f'(0) = 0\) So from the given information above here, we can construct a original function like that:\(\Large\displaystyle f(x) = \int_{0}^{x} 10e^{-2t} - 40 dt + 0\) Use u-substitution to find the function. Hope this helps.
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