Integrate xe^(x^2)
Use u-substitution. \[u = x^2\]\[du = 2xdx\] \[\frac{ du }{ 2 }=xdx\] \[\int\limits \frac{ 1 }{ 2 }e^udu = \frac{ 1 }{ 2 } \int\limits e^udu\] You can finish it from here.
so you can eliminate the x by the chain rule and not have to integrate it?? what is it was to integrate x^2 e^(x^2)? would only one x cancel and then you have to do the product of them?
Wait, is the function yo are being asked to integrate: \[\int\limits x^2 e^{x^2}dx \] OR \[\int\limits xe^{x^2}dx\]
the second one... i just want to make sure i got the rules right and understand in case it was the first one.
Well, you would use a different method for the first one (integration by parts), not substitution method.
which is to integrate the first times the second, plus integrate the second times the first?
Are you referring to parts? It's something like that. But not quite. It's something like this: \[fg - \int\limits gf'\]
okay well thank you for the help
I would follow the first method I showed you for the initial function you are integrating. It's definitely more cleaner than using parts.
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