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Mathematics 4 Online
OpenStudy (anonymous):

Integrate xe^(x^2)

OpenStudy (abb0t):

Use u-substitution. \[u = x^2\]\[du = 2xdx\] \[\frac{ du }{ 2 }=xdx\] \[\int\limits \frac{ 1 }{ 2 }e^udu = \frac{ 1 }{ 2 } \int\limits e^udu\] You can finish it from here.

OpenStudy (anonymous):

so you can eliminate the x by the chain rule and not have to integrate it?? what is it was to integrate x^2 e^(x^2)? would only one x cancel and then you have to do the product of them?

OpenStudy (abb0t):

Wait, is the function yo are being asked to integrate: \[\int\limits x^2 e^{x^2}dx \] OR \[\int\limits xe^{x^2}dx\]

OpenStudy (anonymous):

the second one... i just want to make sure i got the rules right and understand in case it was the first one.

OpenStudy (abb0t):

Well, you would use a different method for the first one (integration by parts), not substitution method.

OpenStudy (anonymous):

which is to integrate the first times the second, plus integrate the second times the first?

OpenStudy (abb0t):

Are you referring to parts? It's something like that. But not quite. It's something like this: \[fg - \int\limits gf'\]

OpenStudy (anonymous):

okay well thank you for the help

OpenStudy (abb0t):

I would follow the first method I showed you for the initial function you are integrating. It's definitely more cleaner than using parts.

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