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Evaluate the limits. Use -∞ or ∞ where appropriate. lim┬(x→-4)((x+4)/(x^2-x-20))
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I am getting... -4+4 on top which should be 0. and -4^2-(-4)-20 on bottom. What????
So bottom would be 16+4 = 20 then 20-20 = 0 so it would be 0/0 right? Which means it's undefined right?
or would I factor out the bottom?
Factor out the bottom to see if anything cancels out first.
I get (x-4)(x+5) so nothing cancels right.
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I think your factoring is a bit off. check your signs.
-4+5 ≠ -1
so then it's (x+4)(x-5).... So the x+4 cancels. Then I get 1/(x-5) if I plug in the -4 I get 1/9???
Right on. Good Job.
-9
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so it's -1/9
yup
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