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Mathematics 8 Online
OpenStudy (anonymous):

Evaluate the limits. Use -∞ or ∞ where appropriate. lim┬(x→-4)⁡((x+4)/(x^2-x-20))

OpenStudy (anonymous):

I am getting... -4+4 on top which should be 0. and -4^2-(-4)-20 on bottom. What????

OpenStudy (anonymous):

So bottom would be 16+4 = 20 then 20-20 = 0 so it would be 0/0 right? Which means it's undefined right?

OpenStudy (anonymous):

or would I factor out the bottom?

OpenStudy (abb0t):

Factor out the bottom to see if anything cancels out first.

OpenStudy (anonymous):

I get (x-4)(x+5) so nothing cancels right.

OpenStudy (abb0t):

I think your factoring is a bit off. check your signs.

OpenStudy (abb0t):

-4+5 ≠ -1

OpenStudy (anonymous):

so then it's (x+4)(x-5).... So the x+4 cancels. Then I get 1/(x-5) if I plug in the -4 I get 1/9???

OpenStudy (abb0t):

Right on. Good Job.

OpenStudy (anonymous):

-9

OpenStudy (anonymous):

so it's -1/9

OpenStudy (abb0t):

yup

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