Question

what is the antiderivative of f'(x)=4/(1-x^2)^(1/2) if f(1/2) = 1?

Answer 1

so it's the stupid chain rule that's messing me up. I have no clue how to find this. Wolfram Alpha throws sin inverse at me!

Answer 2

Chain rule? Then, does that mean you are referring to derivatives?

Answer 3

B/c the anti-derivative of that would technically be arcsine.

Answer 4

integrate using x=sin u

Answer 5

well, I took a stab at it and got 8(1/2-1/3(x)^3)^(-1/2) but when I tried to check it, the chain rule throws it all off! We haven't gotten to integrating yet! I don't even know what that means.

Answer 6

Okay, I guess I have to review this chapter in my textbook. I thought this homework assignment would only be based on what we did in class....

Answer 7

Yes, I get it now. It's an identity. The d/dx of sin inverse is 1/(1-x)^2. Thanks again!