Question

HELP PLEASE!!!!!!!! Solve the following equation algebraically. See below

Answer 1

\[\frac{ 2 }{3 }=2-\frac{ 5x-3 }{x-1 }\]

Answer 2

do you want just the answer?

Answer 3

i want to know how to solve it

Answer 4

well first multiply by 3, then multiply by x-1, then collect like terms and isolate x

Answer 5

ok so i need to multiply all sides by 3 and x-1

Answer 6

i got 2(x-1)=3(2)+2(x-1)-3(5x-3)

Answer 7

@Kuoministers can you help me please

Answer 8

hey mate

Answer 9

hi

Answer 10

yea so just did what he said, which is to multiply everything by 3 and x-1

Answer 11

that would give you
\[2 = 6 - \frac{ 15x-9}{ 3x - 3 }\]

Answer 12

hmm you would multiply everything by 3x - 3 :P now

Answer 13

cant you cross multiply the 3 and x-1 at the same time

Answer 14

\[6x- 6=18x-18x+(15x - 9)(3x-3)\]

Answer 15

maybe but i dont think so as there is a 2 in the equation

Answer 16

\[6x - 6 = 18x - 18 + 45x ^{2} - 45x -27x + 27\]

Answer 17

\[0=45x ^{2} - 60 +15\]

Answer 18

now i think you can work it out

Answer 19

hint: 2 numbers you can use is 15 and 45

Answer 20

should that be 60x

Answer 21

oh yes my bad

Answer 22

can you work it out now?

Answer 23

yes thank u

Answer 24

Hint:


\[\Large \frac{ 2 }{3 }=2-\frac{ 5x-3 }{x-1 }\]


Multiply every term by the LCD 3(x-1) to get


\[\Large \frac{ 2 }{3 }*3(x-1)=2*3(x-1)-\frac{ 5x-3 }{x-1 }*3(x-1)\]


\[\Large 2(x-1)=6(x-1)-3(5x-3)\]

Answer 25

2x-2=6x-6-15x-9

Answer 26

now i need to combine like terms

Answer 27

should be +9 at the end, not -9

Answer 28

so x=5/11

Answer 29

yep

Answer 30

so to check my answer i could replace x with 5/11 and it should work out to equal 2/3

Answer 31

yes, ideally replacing each x with the supposed solution should make both sides equal to one another

Answer 32

ok thank you very much

Answer 33

you're welcome