In the equation f(x)=7, using the formula f(x+h)-f(x)/h, how do they get 0. How does f(x+h)=0 also?
I mean =7
i would think, by h =0 is the only way to get f(x+h) = 7
how do we know h=0?
Okay, I understand now. How do we get rid of the bottom h then?
h is still zero
but if that would leave the equation 0/0 which is undefine? How can i get rid of the h?
your function is a constant, so \(f(x)=7\) and also \(f(x+h)=7\)
you get \[\lim_{h\to 0}\frac{7-7}{h}=\lim_{h\to 0}0=0\]
so what happens to the denominator?
any fraction with zero in the numerator is zero
you are taking a limit, not replacing \(h\) by 0 your difference quotient is identically zero for all values of \(h\neq 0\)
so the denominator does not matter?
you are taking a limit as the denominator goes to zero, but the whole reason for calling it "the limit" is that you cannot replace \(h\) by zero in other words when you take a limit as say \(h\to a\) you are assuming that \(h\) is close but not equal to \(a\)
so if \(h\neq 0\) then \(\frac{0}{h}=0\) always
and therefor the limit is zero in any case \(y=7\) is a horizontal line and as such the slope is zero for sure
Okay, thank you, im kind of getting the jist of what your saying
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