The bar representing which of the following probabilities on a histogram would be the highest? A.1/30 B.1/15 C.1/10 D.2/15
help asap !! please
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jimthompson5910 (jim_thompson5910):
convert each fraction to a decimal number and that will allow you to compare the numbers easier
jimthompson5910 (jim_thompson5910):
for example
1/30 = 0.0333333...
1/15 = 0.0666667
So we can see that 1/15 is larger than 1/30 since 0.0666667 is larger than 0.033333
OpenStudy (anonymous):
so it would be b?
jimthompson5910 (jim_thompson5910):
if you just had those two fractions, yes
but you need to compare the rest of the fractions
OpenStudy (anonymous):
c is 0.1 and d is 0.13 so than it would be d than?
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jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
oh okay thank you,
jimthompson5910 (jim_thompson5910):
you're welcome
OpenStudy (anonymous):
Do you know anything about this?
jimthompson5910 (jim_thompson5910):
that's the combination of choosing 7 things out of 9
basically it's asking "how many ways are there to choose 7 items out of 9 where order does not matter"
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OpenStudy (anonymous):
I don't understand, cause the choices are A.66 B.55 C.36 D.45
jimthompson5910 (jim_thompson5910):
have you learned about permutations?
OpenStudy (anonymous):
no , this is online math,
jimthompson5910 (jim_thompson5910):
I figured that, but I would have also figured that you have learned about permutations or combinations by now
jimthompson5910 (jim_thompson5910):
seems odd how they skipped over that
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OpenStudy (anonymous):
No, it was never on any of the information given to me for each section,
jimthompson5910 (jim_thompson5910):
well luckily we can take advantage of the fact that 9 C 7 = 9 C 2
9 C 2 = (9*8)/2 = ???
OpenStudy (anonymous):
36
jimthompson5910 (jim_thompson5910):
so 9 C 7 = 36 as well
jimthompson5910 (jim_thompson5910):
you can also use Pascals triangle to get the same thing
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OpenStudy (anonymous):
what about this? If a probability distribution is 5/12,1/6 ,1/4 , x, what is the value of x? A.1/3 B.1/6 C.1/12 D.1/4
jimthompson5910 (jim_thompson5910):
add up all the fractions including x and set it equal to 1
then solve for x
jimthompson5910 (jim_thompson5910):
5/12 + 1/6 + 1/4 + x = 1
solve this for x
OpenStudy (anonymous):
i don't know, 7/22?
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
oh wait, one sec
OpenStudy (anonymous):
i don't undersad
OpenStudy (anonymous):
understand*
jimthompson5910 (jim_thompson5910):
what do you get when you combine these fractions
5/12 + 1/6 + 1/4
OpenStudy (anonymous):
i don't know , cause they have different numbers do i need them both to get 12?
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jimthompson5910 (jim_thompson5910):
yes you need all the denominators to be equal to 12
OpenStudy (anonymous):
12/12?
OpenStudy (anonymous):
you multiply 6 with 2 and 4 with 3 ,
jimthompson5910 (jim_thompson5910):
5/12 = 5/12
1/6 = 2/12
1/4 = 3/12
-----------------
5/12 + 1/6 + 1/4
is the same as
5/12 + 2/12 + 3/12
OpenStudy (anonymous):
10/12 reduced to 5/6?
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jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
thaat not right
jimthompson5910 (jim_thompson5910):
we're not done yet
OpenStudy (anonymous):
oh
jimthompson5910 (jim_thompson5910):
but we're on the right path to getting there
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OpenStudy (anonymous):
okay whats next?
jimthompson5910 (jim_thompson5910):
5/12 + 1/6 + 1/4 + x = 1
is the same as
5/6 + x = 1
Now subtract 5/6 from both sides to isolate x
5/6 + x - 5/6 = 1 - 5/6
x = 1 - 5/6
x = ???
OpenStudy (anonymous):
4/6 reduced to 2/3? but that not on there either?
OpenStudy (anonymous):
nevermind 0.16666666666
jimthompson5910 (jim_thompson5910):
no not this
|dw:1359342264313:dw|
but this
|dw:1359342279294:dw|