5v√ 75vw^2 + w√ 27v^3 simplify
anybody know?
simplify both radicals... \[5v \sqrt{25w^2 \times 3v} + w \sqrt{9v^2 \times 3v}\] this can be written as \[5v \sqrt{25w^2} \times \sqrt{3v} + \sqrt{9v^2} \times \sqrt{3v}\] hopefully this helps... you can take the square root of the perfect squares... and you'll be teft with the same radical that can be added.
im lost as heck bro
ok... so I split 75vw^2 into 2 perfect squares 25 x 3 = 75 v x w^2 = vw^2 so 75 vw^2 can be written as 25w^2 x 3v does that make sense...?
ya
ok... so you are happy to take the square root of 25w^2..? the same thing has been donw with the 2nd radical 27 = 9 x 3 v^3 = v^2 x v so 27v^3 = 9v^2 x 3v take the square root of 9v^2..... the 3v in both cases will remain in the radical.
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